| Chapter | 
 
 
As we know, the
Gauss Law of Electric Field defines the relationship between electric charge
and electric field as follows: 
 
 (4.1)
                                                                                                                  (4.1)
 
In
which  is the electric field
strength, and
 is the electric field
strength, and  is the electric charge density.
is the electric charge density.
If
we combine the Gauss Law of Electric Field equation (4.1) and the electric
charge density distribution equation (2.1), we will obtain the follows electric field solution:
 
 (4.2)
                                                                       (4.2)
 
Below, we will prove that the above equation (4.2)
satisfies the Gauss Law of Electric Field.
 
As we know the gradient  in spherical coordinate is:
 in spherical coordinate is:
 

 
From equation (4.2), thus:
 
 (4.3)
                                            (4.3)
 
Thus:
                                               
 (4.4)
                                                 (4.4)
 
 (4.5)
                          (4.5)
 
Therefore:
 
 (4.6)
                          (4.6)
 
And so:
                                   
 (4.7)
                                                                                   (4.7)
 
If
we combine equation (4.7) and (2.1), then we will get the Gauss Law
of Electric Field.
 
 
 
 
Thus we
have proved that the electric field equation (4.2) indeed satisfies the Gauss
Law of Electric Field.
 
 
    
  
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